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Let $$f : R \rightarrow R, g : R \rightarrow R$$ and $$h : R \rightarrow R$$ be differentiable functions such that $$f(x) = x^3 + 3x + 2, g(f(x)) = x$$ and $$h(g(g(x))) = x$$ for all $$x \in R$$. Then
$$g'(2) = \frac{1}{15}$$
$$h'(1) = 666$$
$$h(0) = 16$$
$$h(g(3)) = 36$$
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