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Question 47

Hoffmann bromamide degradation of benzamide gives product A, which upon heating with CHCl$$_3$$ and NaOH gives product B. The structures of A and B are:

Hoffman degradation of Benzamide gives aniline. Aniline upon treatment with CHCl$$_3$$ and NaOH (carbylamine test) gives benzene carbylamine.

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