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For a network shown in figure, a steady state is reached with switch k is open. Switch is closed at time t = 0. Calculate $$\left(\frac{di_1}{dt}\right)$$ and $$\left(\frac{di_2}{dt}\right)$$ at t = 0+
16.67 A/sec and $$-4.16 \times 10^4$$ A/sec
16.67 A/sec and $$-3.33 \times 10^4$$ A/sec
25 A/sec and $$-4.16 \times 10^4$$ A/sec
25 A/sec and $$-3.33 \times 10^4$$ A/sec
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