Based on the following table and answer the given questions.
Number of Assistant Professors in university J = $$\frac{72}{100} \times 300 = 216$$
Number of Assistant Professors in university L = $$\frac{60}{100} \times 160 = 96$$
Number of Assistant Professors in university M = $$\frac{55}{100} \times 180 = 99$$
=> Total number of Assistant Professors in universities J, L and M = 216 + 96 + 99 = 411
$$\therefore$$ Required average = $$\frac{411}{3} = 137$$
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