In ammonia the bond angle is $$107^\circ48'$$ while in $$\mathrm{SbH_3}$$ the bond angle is about $$91^\circ18'$$. The correct explanation is

A

The orbitals of Sb used for formation of the Sb-H bond are almost pure p orbitals

B

Sb has larger size compared to N

C

Sb has more metallic character than N

D

All the statements are correct