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Question 46
$$ If \sin\theta = \cos\theta, and \theta $$ is acute, the value of $$ 2\sin^{2} \theta - 3\cos^{2} \theta is : $$
Solution
$$\sin\theta = \cos\theta when \theta=45\degree$$
So , $$ 2\sin^{2} \theta - 3\cos^{2} \theta$$
=$$\frac{2}{2} - \frac{3}{2}$$
=$$\frac{-1}{2}$$
So, the answer would be option b)$$\frac{-1}{2}$$.
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