Solution
The number of digits in $$4^{50}$$ is $$\log\ 4^{50}=50\ \log\ 4$$
or 100 log 2 = 100(0.3010)=30.10
Number of digits 30+1=31
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The number of digits in $$4^{50}$$ is $$\log\ 4^{50}=50\ \log\ 4$$
or 100 log 2 = 100(0.3010)=30.10
Number of digits 30+1=31
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