SRCC GBO 2009 Question Paper

Question 46

If $$\log 2 = 0.3010$$, then the number of digits in $$4^{50}$$ is

Solution

 The number of digits in $$4^{50}$$ is $$\log\ 4^{50}=50\ \log\ 4$$

or 100 log 2 = 100(0.3010)=30.10

Number of digits 30+1=31

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