The $$pK_a$$ of a weak acid, HA, is 4.80. The $$pK_b$$ of a weak base, BOH, is 4.78. The pH of an aqueous solution of the corresponding salt, BA, will be

The pH of an aqueous solution of a salt formed by a weak acid ($$HA$$) and a weak base ($$BOH$$), you can use the standard salt hydrolysis formula:

$$\text{pH} = 7 + \frac{1}{2}(pK_a - pK_b)$$

Given Data:

• $$pK_a \text{ of } HA = 4.80$$
• $$pK_b \text{ of } BOH = 4.78$$

Step-by-Step Calculation:

1. Substitute the values into the formula:
   $$\text{pH} = 7 + \frac{1}{2}(4.80 - 4.78)$$
2. Simplify inside the parentheses:
   $$\text{pH} = 7 + \frac{1}{2}(0.02)$$
3. Calculate the final pH:
   $$\text{pH} = 7 + 0.01 = 7.01$$

Hence, Option C is Correct.