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Let $$f(x) = \begin{cases}x^2 \mid \cos \frac{\pi}{x} \mid & x \neq 0\\0, & x = 0\end{cases}, x \in R$$, then f is
differentiable both at x = 0 andat x = 2
differentiable at x = 0 but not differentiable at x = 2
not differentiable at x = 0 butdifferentiable at x = 2
differentiable neither at x = 0 nor at x =2
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