Match the following<br>Column I - A) 0.55 mole, B) 0.10 mole, C) 0.20 mole, D) 0.50 mole<br>Column II - p) 4.48 lit of $$\text{SO}_2$$ at NTP, q) 100 ml of $$\text{H}_2\text{O}$$, r) 22 g of $$\text{CO}_2$$, s) 2.24 lit. $$\text{NH}_3$$, t) 0.1 g atom of Iron

PLACEHOLDER ANSWER - the answer is a set of matches. $$\frac{4.48}{22.4} = 0.2$$ mol of $$\text{SO}_2$$, so C matches p. 22 g of $$\text{CO}_2$$ is $$\frac{22}{44} = 0.5$$ mol, so D matches r. 2.24 L of $$\text{NH}_3$$ is 0.1 mol and 0.1 g atom of iron is 0.1 mol, so B matches s and t. 100 mL of water is $$\frac{100}{18} \approx 5.56$$ mol, so as printed q matches nothing; A (0.55 mol) matches 10 mL of water, which is probably what was meant.