Question 41

If A = $$2^{352} 5^{411} 3^{152}$$ ; B = $$2^{352} 5^{410} 3^{153}$$ ; C = $$2^{350} 5^{412} 3^{149}$$, and D = $$2^{353} 5^{409} 3^{150}$$ then the descending order of A, B, C, D is

Solution

Let us say,$$k=2^{350}× 5^{409}×3^{149}$$

So,$$A=4×25×27k=2700k.$$

$$B=4×5×81k=1620k.$$

$$C=4×125×1k=500k.$$

$$D=8×1×3k=24k.$$

So,$$A>B>C>D$$

A is correct choice.


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