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Question 41
If A = $$2^{352} 5^{411} 3^{152}$$ ; B = $$2^{352} 5^{410} 3^{153}$$ ; C = $$2^{350} 5^{412} 3^{149}$$, and D = $$2^{353} 5^{409} 3^{150}$$ then the descending order of A, B, C, D is
Solution
Let us say,$$k=2^{350}× 5^{409}×3^{149}$$
So,$$A=4×25×27k=2700k.$$
$$B=4×5×81k=1620k.$$
$$C=4×125×1k=500k.$$
$$D=8×1×3k=24k.$$
So,$$A>B>C>D$$
A is correct choice.
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