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A metal oxide has formula $$\text{X}_2\text{O}_3$$ it can be reduced by hydrogen to give free metal and water. 0.1596 g of metal oxide requires 6 mg of hydrogen for complete reduction. The atomic weight of the metal is __________.
Correct Answer: 55.8
$$\text{X}_2\text{O}_3 + 3\text{H}_2 \rightarrow 2\text{X} + 3\text{H}_2\text{O}$$. 6 mg of hydrogen is 0.003 mol, so the oxide is 0.001 mol and its molar mass is $$\frac{0.1596}{0.001} = 159.6$$. Then $$2X + 48 = 159.6$$ gives $$X = 55.8$$ (iron).
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