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The area of the region $${(x,y): xy \leq 8, 1 \leq y \leq x^2}$$ is
$$16\log_e 2 - \frac{14}{3}$$
$$8\log_e 2 - \frac{14}{3}$$
$$16\log_e 2 - 6$$
$$8\log_e 2 - \frac{7}{3}$$
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