Question 40

If one of the zeros of the quadratic polynomial $$(k — 1)x^2 + kx + 1$$ is -3 then the value of $$k =$$

Solution

Given

one of the zeros of the quadratic polynomial $$(k — 1)x^2 + kx + 1$$ is -3

so put value of x=-3

$$(k — 1)(-3)^2 + k(-3) + 1=0$$

$$(k — 1)9 - 3k + 1=0$$

$$9k-9 - 3k + 1=0$$

$$6k-8=0$$

$$k=\frac{4}{3}$$

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