Question 40

A small metallic spherical ball is dropped from height h on the wet clay on the Earth surface. It travels distance S inside the wet clay before it stops. The uniform resistive force offered by the clay to the ball, as it penetrates a vertical distance S through the clay, is (the size of the ball is ignored as compared to S)

The ball starts and ends at rest, so the work done by gravity over the total fall $$(h + S)$$ equals the work done against the clay over distance S. Thus $$mg(h + S) = FS$$, giving $$F = mg\left(1 + \frac{h}{S}\right)$$.

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