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The area of the region between the curves $$y = \sqrt{\frac{1 + \sin x}{\cos x}}$$ and $$y = \sqrt{\frac{1 - \sin x}{\cos x}}$$ bounded by the lines x = 0 and $$x = \frac{\pi}{4}$$ is
$$\int_{0}^{\sqrt{2}-1}\frac{t}{(1+t^2)\sqrt{1-t^2}}dt$$
$$\int_{0}^{\sqrt{2}-1}\frac{4t}{(1+t^2)\sqrt{1-t^2}}dt$$
$$\int_{0}^{\sqrt{2}+1}\frac{4t}{(1+t^2)\sqrt{1-t^2}}dt$$
$$\int_{0}^{\sqrt{2}+1}\frac{t}{(1+t^2)\sqrt{1-t^2}}dt$$
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