Take the numbers 1, 2, 3, 4, 5, 6, 7 and 8. We have to make two groups, A and B, each containing four numbers such that 

(a) The sum of the numbers in group A is equal to the sum of the numbers in group B, 

(b) Group A has a number such that when it is moved from group A to group B, the sum of the five numbers in group B is equal to twice the sum of the 3 numbers in group A, and 

(c) Group B has a number such that when it is moved to group A, the sum of the three numbers in group B is $$\frac{5}{7}$$ of the sum of the 5 numbers in group A. Find the numbers in groups A and B.