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A square ABCD is inscribed in a quarter circle where B is on the circumference of the circle and D is the center of the circle. The length of diagonal AC of the square, if the circle's radius is 5, is
Since D is the centre and B lies on the circle, the diagonal $$DB$$ is a radius, so $$DB = 5$$. The two diagonals of a square are equal, so $$AC = DB = 5$$.
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