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The unit digit in the product of $$(8267)^{153} \times (341)^{72}$$ is the same as the unit digit in the product of $$(7)^{153} \times (1)^{72}$$
1 raised to anything is 1.
7 has a cyclicity of 4. Thus, $$7^{153} = 7^1 = 7$$
Hence, option C is the correct answer.
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