Question 39

The population of a city was 66,150 in 2005. If the population increased at the rate of $$5\%$$ per annum, then the population in 2003 was

Solution

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The population grew for 2 years at $$5\%$$, so $$P \times (1.05)^2 = 66150$$. Hence $$P = \frac{66150}{1.1025} = 60000$$.

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