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On decomposition of $$\text{NH}_4\text{HS}$$ the following equation is established $$\text{NH}_4\text{HS}(s) \rightleftharpoons \text{NH}_3(g) + \text{H}_2\text{S}(g)$$. If the total pressure is $$p$$ atmospheres then the equilibrium constant $$K_p$$ will be equal to $$\frac{p^2}{x}\text{ atm}^2$$ where $$x$$ is ___
Correct Answer: 4
The two gases form in equal amounts, so each has partial pressure $$\frac{p}{2}$$. Then $$K_p = p_{\text{NH}_3} \cdot p_{\text{H}_2\text{S}} = \frac{p}{2} \cdot \frac{p}{2} = \frac{p^2}{4}$$, so $$x = 4$$.
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