Question 39

Jar A contains 'X' litre of pure milk only. A 27 litre mixture of milk and water in the respective ratio of 4 : 5, is added to jar A. The new mixture thus formed in jar A contains 70% milk, what is the value of X ?

Solution

Quantity of milk in 27 litre mixture = $$\frac{4}{4 + 5} \times 27 = 12$$ litre

Quantity of water = $$27 - 12 = 15$$ litre

Ratio of milk and water in the new mixture = $$70 : 30 = 7 : 3$$

Acc to ques,

=> $$\frac{X + 12}{15} = \frac{7}{3}$$

=> $$3X + 36 = 15 \times 7 = 105$$

=> $$3X = 105 - 36 = 69$$

=> $$X = \frac{69}{3} = 23$$ litre

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