If $$\frac{2a+b}{a+4b}$$ = 3, then find the value of $$\frac{a+b}{a+2b}$$
Given $$\frac{2a+b}{a+4b}$$=3
=>$$2a+3b=3a+12b$$
$$=>a=-11b$$
Substituting this in $$\frac{a+b}{a+2b}$$
=$$\frac{-10b}{9b}$$
=$$\frac{10}{9}$$
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