Question 39

If $$\frac{2a+b}{a+4b}$$ = 3, then find the value of $$\frac{a+b}{a+2b}$$

Solution

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Given $$\frac{2a+b}{a+4b}$$=3

=>$$2a+3b=3a+12b$$

$$=>a=-11b$$

Substituting this in $$\frac{a+b}{a+2b}$$

=$$\frac{-10b}{9b}$$

=$$\frac{10}{9}$$

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