Join Our JEE Preparation Group
Prep with like-minded aspirants; Get access to free daily tests and study material.
Sign in
Please select an account to continue using cracku.in
↓ →
Join Our JEE Preparation Group
Prep with like-minded aspirants; Get access to free daily tests and study material.
Arrange in the increasing order of ionic radii for isoelectronic species $$\text{K}^+$$, $$\text{S}^{2-}$$, $$\text{Ca}^{2+}$$, $$\text{Cl}^-$$ ____________
Correct Answer: 0
PLACEHOLDER ANSWER - the answer is an order of ions. All four have 18 electrons, so the radius decreases as the nuclear charge increases (Ca 20, K 19, Cl 17, S 16). The increasing order is $$\text{Ca}^{2+} < \text{K}^+ < \text{Cl}^- < \text{S}^{2-}$$.
Was this solution helpful?
Predict your JEE Main percentile, rank & performance in seconds
Educational materials for JEE preparation
Ask our AI anything
AI can make mistakes. Please verify important information.
AI can make mistakes. Please verify important information.