Question 38

Two statement are given below.<br>Statement (I) - The sum of $$(4a + 2ab - c)$$ and $$(6a + 3c)$$ is $$(10a + 2ab + 4c)$$.<br>Statement (II) - $$(6a + 3c)$$ when subtracted from $$(4a + 2ab - c)$$ gives $$(-2a + 2ab - 4c)$$.<br>Choose the correct answer from the options given below.

Solution

The sum is $$(4a + 2ab - c) + (6a + 3c) = 10a + 2ab + 2c$$, not $$10a + 2ab + 4c$$, so Statement (I) is false. The difference is $$(4a + 2ab - c) - (6a + 3c) = -2a + 2ab - 4c$$, so Statement (II) is true.

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