Question 38

The minimum frequency of photon required to break a particle of mass 15.348 amu into $$4\alpha$$ particles is ____ kHz.
[mass of He nucleus$$=4.002amu, 1 amu=1.66\times10^{-27}kg,h=6.6\times10^{-34}J.s $$ and $$ c=3\times10^{8}m/s$$]

Create a FREE account and get:

  • Free JEE Mains Previous Papers PDF
  • Take JEE Mains paper tests