Compound $$A$$ formed in the following reaction reacts with $$B$$ gives the product $$C$$. Find out $$A$$ and $$B$$.

A

$$A = CH_3-C \equiv C^- Na^+$$, $$B = CH_3-CH_2-CH_2-Br$$

B

$$A = CH_3-CH=CH_2$$, $$B = CH_3-CH_2-CH_2-Br$$

C

$$A = CH_3-CH_2-CH_3$$, $$B = CH_3-C \equiv CH$$

D

$$A = CH_3-C \equiv C^- Na^+$$, $$B = CH_3-CH_2-CH_3$$