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$$SnCl_2 + 2HgCl_2 \rightarrow Hg_2Cl_2 + SnCl_4$$
In the given reaction:
$$HgCl_2$$ is oxidised
$$SnCl_2$$ is oxidised
$$Hg_2Cl_2$$ is oxidised
$$SnCl_2$$ is reduced
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