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Question 37
An object of 5.0 kg is raised through a height of 2.0 m. The work done in the process is: (Take g = 9.8 m/s$$^2$$)
Solution
given,
mass of the object=5kg
height attained =2m
acceleration due to gravity= 9.8m/s^2
work done= Fs
work done =mgh (∵ F can also be written as mg)
work done=$$5\times 9.8\times 2$$
∴work done=98 J
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