Question 37

An object of 5.0 kg is raised through a height of 2.0 m. The work done in the process is: (Take g = 9.8 m/s$$^2$$)

Solution

given,

mass of the object=5kg

height attained =2m

acceleration due to gravity= 9.8m/s^2

work done= Fs

work done =mgh (∵ F can also be written as mg)

work done=$$5\times 9.8\times 2$$

∴work done=98 J


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