$$Fe^{3+}$$ is reduced to $$Fe^{2+}$$ by using

A

$$H_2O_2$$ in presence of NaOH

B

$$Na_2O_2$$ in water

C

$$H_2O_2$$ in presence of $$H_2SO_4$$

D

$$Na_2O_2$$ in presence of $$H_2SO_4$$