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$$Fe^{3+}$$ is reduced to $$Fe^{2+}$$ by using
$$H_2O_2$$ in presence of NaOH
$$Na_2O_2$$ in water
$$H_2O_2$$ in presence of $$H_2SO_4$$
$$Na_2O_2$$ in presence of $$H_2SO_4$$
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