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Three parallel plate capacitors $$C_1$$, $$C_2$$ and $$C_3$$ each of capacitance 5 $$\mu$$F are connected as shown in figure. The effective capacitance between points A and B, when the space between the parallel plates of $$C_1$$ capacitor is filled with a dielectric medium having dielectric constant of 4, is :
Initially
$$C_1=C_2=C_3=5\mu F$$
Dielectric constant 4 is inserted in $$C_1$$, so
$$C_1'=4(5)=20\mu F$$
From circuit:
These two branches are in parallel.
$$C_{top}=\frac{C_1'C_2}{C_1'+C_2}$$
$$=\frac{20\cdot5}{20+5}$$
$$\frac{100}{25}=4\mu F$$
Parallel combination:
$$C_{eq}=C_{top}+C_3$$
$$=4+5$$
$$=9\mu F$$
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