In a Young's double slit experiment the intensity at a point where the path difference is $$\frac{\lambda}{6}$$ ($$\lambda$$ being the wavelength of the light used) is $$I$$. If $$I_0$$ denotes the maximum intensity, $$\frac{I}{I_0}$$ is equal to

A

$$\frac{1}{\sqrt{2}}$$

B

$$\frac{\sqrt{3}}{2}$$

C

$$1/2$$

D

$$3/4$$