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When $$2^{256}$$ is divided by 17, the remainder would be
1
16
14
None of these
$$2^4 = 16 = -1$$ (mod $$17$$) So, $$2^{256} = (-1)^{64} $$(mod $$17$$) $$= 1$$ (mod $$17$$) Hence, the answer is 1. Option a).
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