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The activity of a radioactive sample decreases to one tenth of the original activity $$A_{0\ }$$ in a period of one year. After 9 more years its activity would be
For radioactive decay, the activity decreases exponentially.
Given that after one year,
$$A=\frac{A_0}{10}$$
Therefore, after each year the activity becomes one-tenth of its previous value.
After a total time of $$10$$ years,
$$A=A_0\left(\frac{1}{10}\right)^{10}$$
$$A=\frac{A_0}{10^{10}}$$
Therefore, $${A=\frac{A_0}{10^{10}}}$$
Hence, the correct option is C.
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