Solution of $$(D^2 + 4)y = \sin^2 x$$, is

A

$$y = A \cos 2x + B \sin 2x - \frac{1}{8} - \frac{x}{8}\sin 2x$$

B

$$y = A \cos 2x + B \sin 2x + \frac{1}{8} + \frac{x}{8}\sin 2x$$

C

$$y = A \cos 2x + B \sin 2x - \frac{1}{8} + \frac{x}{8}\sin 2x$$

D

$$y = A \cos 2x + B \sin 2x + \frac{1}{8} - \frac{x}{8}\sin 2x$$