In an a.c. circuit the voltage applied is $$E = E_0 \sin \omega t$$. The resulting current in the circuit is $$I = I_0 \sin\left(\omega t - \frac{\pi}{2}\right)$$. The power consumption in the circuit is given by

A

$$P = \frac{E_0 I_0}{\sqrt{2}}$$

B

$$P = \text{zero}$$

C

$$P = \frac{E_0 I_0}{2}$$

D

$$P \sqrt{2} E_0 I_0$$