Question 33

At 5% simple interest per annum a certain sum yields a total amount of ₹ 2,790 at the end of $$3\frac{1}{4}$$ years. The sum invested was:

Solution

$$P = \frac{S.I. \times 100}{RT}$$

$$\frac{P\times{5\times\frac{13}{4}}}{100} = {SI}$$
A=P+SI

$$2790=P+\frac{P\times{5\times\frac{13}{4}}}{100}$$

$$2790=\frac{400P+{P\times{5\times{13}}}}{{400}}$$

$$2790\times400=465P$$

$$2400=P$$

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