Join Our JEE Preparation Group
Prep with like-minded aspirants; Get access to free daily tests and study material.
Sign in
Please select an account to continue using cracku.in
↓ →
Join Our JEE Preparation Group
Prep with like-minded aspirants; Get access to free daily tests and study material.
A radio active cobalt used for cancer chemotherapy having half life 3 hrs. It was sent to a hospital which is received after 12 hrs. At the time of receiving it was left only 3 gms. What was the initial amount (in grams) ___________.
Correct Answer: 48
12 hours is $$\frac{12}{3} = 4$$ half-lives, so the amount falls to $$\left(\frac{1}{2}\right)^4 = \frac{1}{16}$$ of the initial value. The initial amount was $$3 \times 16 = 48\text{ g}$$.
Was this solution helpful?
Predict your JEE Main percentile, rank & performance in seconds
Educational materials for JEE preparation
Ask our AI anything
AI can make mistakes. Please verify important information.
AI can make mistakes. Please verify important information.