If $$\frac{\sin^4x}{2}+\frac{\cos^4x}{3} = \frac{1}{5}$$ then

A

$$\tan^2 x = \frac{2}{3}$$

B

$$\frac{\sin^8 x}{8}+\frac{\cos^8 x}{27} = \frac{1}{125}$$

C

$$\tan^2 x = \frac{1}{3}$$

D

$$\frac{\sin^8 x}{8}+\frac{\cos^8 x}{27} = \frac{2}{125}$$