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what is the value of $$\frac{\log_{27}{9} \times \log_{16}{64}}{\log_{4}{\sqrt2}}$$?
$$\frac{\log_{27}{9} \times \log_{16}{64}}{\log_{4}{\sqrt2}}$$?Â
=$$\frac{\ \log_{3^3}3^2\times\ \log_{2^4}2^6}{\log_{\left(\sqrt{\ 2}\right)^4}\sqrt{\ 2}}$$
=$$\frac{\ \ \frac{\ 2}{3}\times\ \frac{\ 6}{4}}{\ \frac{\ 1}{4}}$$
=4
D is the correct answer.
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