If 0, 1, 2, 3,..., 9 is written as a, b, c, d,...,j, then find $$dc \times f-(bf-d) \times d$$.
Given : $$a=0$$, $$b=1$$, $$c=2$$, $$d=3$$, ..........., $$i=8$$ and $$j=9$$
To find : $$dc \times f-(bf-d) \times d$$
Solution : $$[32\times5]-(15-3)\times3$$
= $$160-(12\times3)=124$$
$$\equiv bce$$
=> Ans - (D)
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