Let $$f \colon \mathbb{R} \rightarrow \mathbb{R}$$ be defined by $$f(x) = x^2$$ for all $$x$$ in $$\mathbb{R}$$. Let $$A = \{4, 3, 0, -1\}$$. Then

A

$$f^{-1}(A)$$ is not defined as $$f^{-1}$$ does not exist

B

For any function $$f \colon P \rightarrow Q$$, if $$T$$ is a subset of $$Q$$, then $$f^{-1}(T)$$ is defined and here $$f^{-1}(A) = \{-2, 2, \sqrt{3}, -\sqrt{3}, 0\}$$

C

$$f^{-1}(A)$$ is not defined as $$-1$$ has no pre-image under the function $$f$$

D

$$f^{-1}(A) = f(A)$$

E

None of these