As (x - 1) and (x + 1) are given in options, let us check by substituting x = 1 and x = - 1.
Substitute x = 1 in the given equation.
x6 - x4 - x5 - x4 + x2 - 4 = 16 - 14 - 15 - 14 + 12 - 4 = - 5
Hence, (x - 1) is not a factor of the given equation.
Now,
Substitute x = - 1in the given equation.
x6 - x4 - x5 - x4 + x2 - 4 = (- 1)6 - (- 1)4 - (- 1)5 - (- 1)4 + (- 1)2 - 4 = - 3
∴ Neither (x - 1) or (x + 1) are the components of (x6 - x4 - x5 - x4 + x2 - 4).
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