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The value of $$n$$ in the molecular formula $$\text{Be}_n\text{Al}_2\text{Si}_6\text{O}_{18}$$ is ___
Correct Answer: 3
The compound is neutral, so $$2n + 2(3) + 6(4) - 18(2) = 0$$, i.e. $$2n + 30 - 36 = 0$$. This gives $$n = 3$$; the mineral is beryl, $$\text{Be}_3\text{Al}_2\text{Si}_6\text{O}_{18}$$.
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