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RRB NTPC 12 April 2016 Shift 3 Question 29

Question 29

A superfast Duronto express running at 90 kmph overtakes a bike miming at 36 kmph in 25 seconds. What is the length of the train in meters?

Solution

Speed of Duronto express = 90 km/h

= 90 × $$\frac{5}{18}$$

= 25 m/s

Speed of Bike = 36 km/h

= 36 × $$\frac{5}{18}$$

= 10 m/s

Now relative speed of Train with respect to Bike

= 25 - 10

= 15 m/s

Now as time is 25 sec

=> Distance travelled by last compartment of train to overcome the bike .

= $$Relative speed \times time$$

= $$15\times 25$$

= 375 m

So length of train



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