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Question 28

To get an output of 1 from the circuit shown in the figure the input must be:

Solution

Let the output of the OR gate be $$X$$. $$X = a + b$$ (OR operation)

$$Y = X \cdot c$$ (AND operation)

$$Y = (a + b) \cdot c$$

Option A: $$(0 + 0) \cdot 1 = 0 \cdot 1 = 0$$

Option B: $$(1 + 0) \cdot 0 = 1 \cdot 0 = 0$$

Option C: $$(1+0) \cdot1 = 1 \cdot 1 = 1$$

Option D: $$(0 + 1) \cdot 0 = 1 \cdot 0 = 0$$

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