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The $$V - I$$ characteristic of a diode is shown in the figure. The ratio of forward to reverse bias resistance is:
Forward bias resistance $$R_f=\frac{\triangle V_f}{\triangle\ I_f}=\frac{\left(0.8-0.7\right)}{\left(20-10\right)\cdot10^{-3}}=10Ω$$
Reverse bias resistance $$R_r=\frac{\triangle V_r}{\triangle\ I_r}=\frac{\left(10-0\right)}{\left(1-0\right)\cdot10^{-6}}=10^7Ω$$
Required ratio, $$\frac{R_f}{R_r}=\frac{10}{10^7}=10^{-6}$$
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