The current flowing through a conductor connected across a source is $$2$$ A and $$1.2$$ A at $$0°$$C and $$100°$$C respectively. The current flowing through the conductor at $$50°$$C will be _____ $$\times 10^2$$ mA.

$$R = \frac{V}{I} \implies R \propto \frac{1}{I}$$

$$R_{100} = R_0(1 + 100\alpha) \implies \frac{2}{1.2} = 1 + 100\alpha \implies 100\alpha = \frac{5}{3} - 1 = \frac{2}{3} \implies \alpha = \frac{2}{300}$$

$$R_{50} = R_0(1 + 50\alpha) \implies \frac{2}{I_{50}} = 1 + 50\left(\frac{2}{300}\right) = 1 + \frac{1}{3} = \frac{4}{3}$$

$$I_{50} = \frac{6}{4} = 1.5\text{ A} = 1500\text{ mA} = 15 \times 10^2\text{ mA}$$