25^[log(5)(12) + 3log(x)(16)] = 9/256

Find x

Equation can be written as 25^(log(5)(12) x 25^(log(x)x16)
25 = 5^2 therefore 5^2log(5)(12) will become 12^ = 144
Because right side is in fraction we know x could be in fraction or with power -1 so putting x = 1/25 or 25^-1
Similar to first equation 25^(3/-1)log25(16) will be equal to 16^-3 = 1/16^3
So 144 x 1/16^3 will be 9/256

TIME - testseries

Hi , can you please provide the solution

@umang Agarwal how much you got on the time test

1/25