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In the reported figure, heat energy absorbed by a system in going through a cyclic process is ___ $$\pi$$ J.
Correct Answer: 100
$$\Delta U = 0 \implies Q = W$$
$$W = \pi \cdot r_P \cdot r_V$$
$$r_P = \frac{40 - 20}{2} = 10\ \text{kPa} = 10 \times 10^3\ \text{Pa}$$
$$r_V = \frac{40 - 20}{2} = 10\ \text{litre} = 10 \times 10^{-3}\ \text{m}^3$$
$$Q = \pi \times (10 \times 10^3) \times (10 \times 10^{-3}) = 100\pi\ \text{J}$$
$$x = 100$$
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